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You want to draw 3 cards from a standard deck of 52 cards without replacing them. How many (no commas needed) outcomes can be produced?

2 Answers

5 votes

Answer:

22,100 possible outcomes.

Explanation:

That is the number of combinations of 3 from 52.

= 52! / 49! 3!

= 52*51*50 / 3*2*1

= 52 * 17 * 25

= 22,100.

User Muratgozel
by
7.7k points
4 votes

Answer:

132,600

Explanation:

We use a permutation to find the answer.

52 x 51 x 50 = 132,600

I'm always happy to help :)

User Jahongir Rahmonov
by
8.8k points

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