Question

A sample of neon gas occupies a volume of 2.8 L at a temp. of 55◦C. The sample is cooled to 30. ◦C, what is the new volume in mL?

a: 2,600 mL
b: 15.4 mL
c: 15 mL
d: 1.5 L

Answer 1

The new volume is 2580 mL.

Step-by-step explanation:

Charles law gives the relationship between volume and temperature of the gas. According to this law, volume of gas is directly proportional to temperature, pressure remains constant.

`(V_1)/(T_1)=(V_2)/(T_2)`

Here,

`V_1=2.8\ L\\\\T_1=55^(\circ) C=328.15\ K\\\\T_2=30^(\circ) C=303.15\ K`

We need to find V₂. So,

`V_2=(V_1T_2)/(T_1)`

`V_2=(2.8* 303.15)/(328.15)\\\\V_2=2.58\ L`

2.58 L = 2580 mL

So, the new volume is 2580 mL.