Question

A child on a swing falls a height of 1m. What speed will the child reach?

Answer 1

Answer:
`v=4.42\ m/s`

Step-by-step explanation:

Given

Child falls a height of
`h=1\ m`

Applying conservation of energy we can write

Loss in Potential energy=Gain in kinetic energy

`mgh=(1)/(2)mv^2`

`v=√(2gh)`

`v=√(2* 9.8* 1)`

`v=√(19.6)`

`v=4.42\ m/s`

Thus child reaches a velocity of 4.42 m/s