Question

If a coin is tossed, a die is rolled, and a candy is taken from

of 14 candies, 7 of which are red, what
8 the probability of getting a red candy, a heads, and an odd number on the die?

Answer 1

⅛

Explanation:

There are two sides of a coin which means that the profanity of getting one side of the coin is ½.

There are 14 candies in total of which 7 are red, meaning that the probability of getting a red candy is 7/14, which is the same as ½.

There are 6 sides to a die, of which 3 sides contain the odd numbers 1,3 and 5. This would mean that the probability of getting an odd number on the die is 3/6, which is the same as ½.

Now to work out the probability of getting a red candy, a heads and an odd number on the die, you have to times the probability of each together to get you final answer.

So it will be, ½×½×½=⅛