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What are the solutions of this quadratic equation?

What are the solutions of this quadratic equation?-example-1
User Dorie
by
8.4k points

2 Answers

4 votes

Answer:

B

Explanation:

2x^2 + 16x - 8 = 0 -->

x^2 + 8x - 4 = 0-->

(-b +/- sqrt(b^2 - 4ac))/2 -->

(-8 +/- sqrt(64 - (-4 * 4)))/2 -->

(-8 +/- sqrt(80))/2 -->

(-8 +/- 4sqrt5)/2 -->

-4 +/- 2sqrt5 (B)

User Novae
by
8.1k points
4 votes

Answer:

B

Explanation:


2x^2+16x-8=0


x=(-16\pm √(256+64))/(4)=(-16\pm 8√(5))/(4)=-4\pm 2√(5), or answer choice B. Hope this helps!

User Rapptz
by
8.1k points

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