Answer:
The number of moles of oxygen present in the crew cabin at any given time is 615.309 moles
Step-by-step explanation:
The given parameters are;
Volume of the crew cabin = 74,000 L
Pressure of the crew cabin = 1.00 atm
Percentage of nitrogen in the mixture of gases in the cabin = 80%
Percentage of oxygen in the mixture of gases in the cabin = 20%
Temperature of the cabin = 20°C = 293.15 K
Therefore, volume of oxygen in the crew cabin = 20% of 74,000 L
Hence, volume of oxygen in the crew cabin =
![(20)/(100) * 74,000 \, L = 14,800 \, L](https://img.qammunity.org/2021/formulas/chemistry/middle-school/i7pt7z31ff9xv9yk7xvaszp8a7rx8but28.png)
From the universal gas equation, we have;
![n = (P * V)/(R * T)](https://img.qammunity.org/2021/formulas/chemistry/high-school/rntfls9m1fyj9w83dumflicrqd9j9x6dpw.png)
Where:
n = Number of moles of oxygen
P = Pressure = 1.00 atm
V = Volume of oxygen = 14,800 L
T = Temperature = 293.15 K
R = Universal Gas Constant = 0.08205 L·atm/(mol·K)
Plugging in the values, we have;
![n = (1 * 14,800 )/(0.08205 * 293.15 ) = 615.309 \, moles](https://img.qammunity.org/2021/formulas/chemistry/middle-school/7akuyubp75sg72o6techqoq6qcu67pozjl.png)
The number of moles of oxygen present in the crew cabin at any given time = 615.309 moles.