Question

Please help me out answering this​

Answer 1

`\\ \rm\Rrightarrow -\sqrt[3]{2x^4y^2}* 3\sqrt[3]{20x^5y}`

• √a√b=√ab

`\\ \rm\Rrightarrow -3√(40x^9y^3)`

• On simplifying

`\\ \rm\Rrightarrow -3(6x^3y\sqrt[3]{5}`

`\\ \rm\Rrightarrow -24x^3y\sqrt[3]{5}`

Answer 2

OPTION A

Explanation:

we start by multiplying both roots.

we then get negative 3 times the third root of: 40 × x^9 × y^3

we then simplify to get:

-24 × x^3 × y × third root of 5