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18 votes
The area formula for rectangular shapes is A=LW. What is the area of a rectangular shape with the dimensions of
\sqrt[4]{11} and
\sqrt[4]{3}?

2 Answers

9 votes

Answer:


\textsf{area}=\sqrt[4]{33}\:\textsf{square units}

Explanation:

Formula

Area of a rectangle = length Ă— width

Given:


  • \textsf{length}=\sqrt[4]{11}

  • \textsf{width}=\sqrt[4]{3}

Substitute given values into the formula:


\implies \textsf{area}=\sqrt[4]{11} \cdot \sqrt[4]{3}


\textsf{Apply radical rule}\quad\sqrt[n]{a} \cdot \sqrt[n]{b}=\sqrt[n]{ab}:


\implies \textsf{area}=\sqrt[4]{11 \cdot 3} =\sqrt[4]{33}\:\textsf{square units}

User Sunny Patel
by
6.7k points
1 vote

Hi!

Given the area formula ~ A = LW

We need to multiply the two values:


\sqrt[4]{11} * \sqrt[4]{3}

Since they have the same root, 4, we can multiply what's inside of the radical and give it the same root.


11*3=33

Now, we apply the same root as before:


\sqrt[4]{33}

Therefore, your answer is
\sqrt[4]{33}

Now, if you need that as a numerical value rather than a radical, it's roughly
2.397

User John Hedengren
by
6.4k points