Answer:
0.083L
Step-by-step explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
Ca(NO3)2 + H2SO4 —> CaSO4 + 2HNO3
Next, we shall determine the number of mole of Ca(NO3)2 needed to produce 0.1 mole of CaSO4.
From the balanced equation above,
1 mole of Ca(NO3)2 reacted to produce 1 mole of CaSO4.
Therefore, 0.1 mole of Ca(NO3)2 will also react to produce 0.1 mole of CaSO4.
Finally, we can determine the volume of Ca(NO3)2 needed for the reaction as follow:
Mole of Ca(NO3)2 = 0.1 mole
Molarity of Ca(NO3)2 = 1.20M
Volume =?
Molarity = mole /Volume
Volume = mole /Molarity
Volume = 0.1/1.2
Volume = 0.083L
Therefore, 0.083L of Ca(NO3)2 is needed for the reaction.