Answer:
The length and the width of the new rectangle are 16.5 inches and 6.6 inches respectively
Explanation:
Given
Shape: Rectangle
![Length = 7.5 inches](https://img.qammunity.org/2021/formulas/mathematics/high-school/dau4udm1p8f6aapwb62ytvuwbt71q2knoa.png)
![Width = 3 inches](https://img.qammunity.org/2021/formulas/mathematics/high-school/dwtgn8cwhezomwu1no7mxcz38kmztf6eat.png)
![Scale factor = 2.2](https://img.qammunity.org/2021/formulas/mathematics/high-school/atcenfdiyxu5jnfj7vh4qx0zw5fybk6s8g.png)
Required
Dimension of the new rectangle
The dimensions of the new rectangle can be solved by multiplying the scale factor by the old dimensions;
This means that
New Length = Scale factor * Old Length
and
New Width = Scale factor * Old Width
Calculating the new length
New Length = Scale factor * Old Length
Substitute 2.2 for scale factor and 7.5 for old length; This gives
![New Length = 2.2 * 7.5 inches](https://img.qammunity.org/2021/formulas/mathematics/high-school/zmctsbi7ivryn5vixou3ijt6fss4gmdnpc.png)
![New Length = 16.5 inches](https://img.qammunity.org/2021/formulas/mathematics/high-school/pvx2d43gt7iv0mf251lrzb3h9qkvbr5jnc.png)
Calculating the new width
New Width = Scale factor * Old Width
Substitute 2.2 for scale factor and 3 for old width; This gives
![New Width = 2.2 * 3 inches](https://img.qammunity.org/2021/formulas/mathematics/high-school/c2h128817z3dsqz9kiajrmdjyuiaoqlw73.png)
![New Width= 6.6 inches](https://img.qammunity.org/2021/formulas/mathematics/high-school/6x0eghrdw5iqf21tyc6s22wm9wkyl3v15g.png)
Hence, the length and the width of the new rectangle are 16.5 inches and 6.6 inches respectively