We have been given that a line
passes through the point (10, 3) and is parallel to the line
. We are asked to find the y-intercept of the line.
First of all we will rewrite our given equation in slope-intercept form as:




We know that slope of parallel lines is equal, so slope of parallel line to our given line would be
.
Now we will use slope-intercept form of equation to find y-intercept.
, where,
m = Slope,
b = The y-intercept.
Let us substitute
and coordinates of point
in above equation as:





Therefore, the y-intercept is 7 and our required equation would be
.