Question

how many liters of bromine are needed to produce 12 moles of Aluminum bromide? The density of bromine is 3.1 m/gl​

Answer 1

0.94 L

Step-by-step explanation:

Step 1: Write the balanced reaction

2 Al + 3 Br₂ = 2 AlBr₃

Step 2: Calculate the moles of Br₂ required to produce 12 moles of AlBr₃

The molar ratio of Br₂ to AlBr₃ is 3:2. Then,

`12molAlBr_3 * (3molBr_2)/(2molAlBr_3) =18molBr_2`

Step 3: Calculate the mass of bromine corresponding to 18 moles

The molar mass of bromine is 159.81 g/mol. Then,

`18mol * (159.81g)/(mol) =2.9 * 10^(3) g`

Step 4: Calculate the volume of bromine corresponding to 2.9 × 10³ g

The density of bromine is 3.1 g/mL. The volume of bromine is:

`2.9 * 10^(3) g * (1mL)/(3.1g) * (1L)/(1000mL) = 0.94 L`