Question

The specific heat of a liquid x is 2.09 cal/g°c. A sample amount of grams of this liquid at 101 k is heated to 225 k. the liquid absorbs 5.23 kcals. what is the sample of liquid in grams? (round off decimal in the answer to nearest tenths)

Answer 1

Answer: 20 grams

Step-by-step explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

`Q=m* c* \Delta T`

Q = Heat absorbed by liquid = 5.23 kcal = 5230 cal (1kcal=1000cal)

C = heat capacity of liquid =
`2.09cal/g^0C`

Initial temperature of the liquid =
`T_i` = 101 K

Final temperature of the liquid =
`T_f` = 225 K

Change in temperature ,
`\Delta T=T_f-T_i=(225-101)K=124K`

Putting in the values, we get:

`5230=m* 2.09cal/g^0C* 124K`

`m=20g`

Thus the sample of liquid in grams is 20