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Prove that for any arithmetic sequence a7+a10=a8+a9
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Prove that for any arithmetic sequence a7+a10=a8+a9

User Ibrahim Najjar
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1 Answer

3 votes

Answer: a3+a6=a4+a5

Step-by-step explanation: since both of those sides there = a17, you can do the same for any other number.

User JessySue
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