We have been given that last month Maria purchased a new cell phone for $500. The store manager told her that her cell phone would depreciate by 70% every 6 months.
We know that an exponential function is in form
, where,
y = Final value,
a = Initial value,
r = Decay rate in decimal form,
x = Time in years.
Let us convert
into decimal form.
![70\%=(70)/(100)=0.70](https://img.qammunity.org/2021/formulas/mathematics/middle-school/2lor9xkxwe43jboxemtb1zr9rp6bw28dn6.png)
Initial value of car is 500, so
.
Since value of phone depreciates every months, so value of phone will depreciate twice in a year.
Upon substituting our given values in exponential decay function, we will get:
![V=500(1-0.70)^(2x)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4wlooajo0liom77ifi627jnt91nfmagv95.png)
To find the value of phone after 2 years, we will substitute
in our equation.
![V=500(1-0.70)^(2(\cdot 2))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/78oxuf0i9tl8dspzec0ughixgnrsj0y24r.png)
![V=500(1-0.70)^(4)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6qwpkt883zhb5wpb7sb9kqwv6zbwykg6aq.png)
Therefore, option D is the correct choice.
Let us simplify our equation.
![V=500(0.30)^(4)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/tdktzcgxnp3kyxukotkjhw4l3gygfta7xs.png)
Therefore, option B is correct as well.