Question

some amusement parks have a ride where people are attached to a long cable, pulled back, and let go, like a pendulum. if the cable is 45.5 m long, what will the period of oscillation be?(unit=s)

Answer 1

Answer: 13.53

Step-by-step explanation:

Answer 2

The period is
`T = 13.53 \ sec`

Step-by-step explanation:

From the question we are told that

The length of the cable is
`L = 45.5 \ m`

Let take acceleration due to gravity as
`g = 9.8 \ m/s^2`

Now the period of the oscillation is mathematically represented as

`T = 2 \pi \sqrt{(L)/(g) }`

substituting values

`T = 2 * 3.142 \sqrt{(45.5)/(9.8) }`

`T = 13.53 \ sec`