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28 votes
28 votes
Find the smallest whole number by which 2268 should be multiplied so as to

get a perfect square number. Also find the square root of the square number
so obtained.

User Miquel Coll
by
3.0k points

2 Answers

17 votes
17 votes

To find the smallest whole number by which 2268 should be multiplied to get a perfect square, we need to factorize 2268 into its prime factors. Then, we can determine which prime factors are needed to make the number a perfect square.

The prime factorization of 2268 is:

2268 = 2^2 * 3^2 * 7 * 9

To make it a perfect square, we need to include the missing factors. In this case, we are missing a factor of 2 and a factor of 3. Therefore, we need to multiply 2268 by 2 * 3 = 6.

2268 * 6 = 13608

Now, we have a perfect square number, 13608.

To find the square root of 13608, we can take the square root of each of its prime factors:

√(2^2 * 3^2 * 7 * 9)

= √2^2 * √3^2 * √7 * √9

= 2 * 3 * √7 * 3

= 6 * √7

So, the square root of the square number 13608 is 6√7.

User Aaron Chen
by
3.3k points
14 votes
14 votes

Answer:

Correct option is B)

252=

2×2

×

3×3

×7

The prime factor 7 does not appear in pairs. To make 252 a perfect square we need one more 7.

Hence, the smallest number by which 252 must be multiplied so that

the product is a perfect square is 7.

And, 252×7=

2×2

×

3×3

×

7×7

252×7

=

2×2

×

3×3

×

7×7

=2×3×7=42

Explanation:

User Suave
by
3.2k points