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A gas of 250 ml at 20°C and 720 Torrs. What volume would the gas occupy at STP ?

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Answer: The gas would occupy volume of 221 ml at STP

Step-by-step explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,


(P_1V_1)/(T_1)=(P_2V_2)/(T_2)

where,


P_1 = initial pressure of gas = 720 torr


P_2 = final pressure of gas = 760 torr (at STP)


V_1 = initial volume of gas = 250 ml


V_2 = final volume of gas = ?


T_1 = initial temperature of gas =
20^oC=273+20=293K


T_2 = final temperature of gas =
273K (at STP)

Now put all the given values in the above equation, we get:


(720* 250)/(293)=(760* V_2)/(273)


V_2=221ml

The gas would occupy volume of 221 ml at STP

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