Question

The volume, in liters, occupied by 2.50 moles of N2 gas.


calculate at STP

Answer 1

Answer: The volume occupied by 2.50 moles of
`N_2` gas at STP is 56.0L

Step-by-step explanation:

According to ideal gas equation:

`PV=nRT`

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = ?

n = number of moles = 2.50

R = gas constant =
`0.0821Latm/Kmol`

T =temperature =
`273K` (at STP)

`V=(nRT)/(P)`

`V=(2.50mol* 0.0821Latm/K mol* 273K)/(1atm)=56.0L`

Thus the volume occupied by 2.50 moles of
`N_2` gas at STP is 56.0L