Question

Water was added to 175 mL of a KOH solution until the volume was 250 mL and the molarity was 0.315 M. What was the molarity of the initial concentrated solution?

Answer 1

Answer: The molarity of the initial concentrated solution is 0.450 M

Step-by-step explanation:

According to the dilution law,

`M_1V_1=M_2V_2`

where,

`M_1` = Molarity of concentrated KOH solution = ?

`V_1` = volume of concentrated KOH solution = 175 ml

`C_2` = concentration of diluted KOH solution= 0.315 M

`V_2` = volume of diluted KOH solution= 250 ml

Putting in the values, we get:

`M_1* 175=0.315* 250`

`M_1=0.450M`

Thus the molarity of the initial concentrated solution is 0.450 M