Question

Need a bit of help with this question:

Answer 1

Firstly let's find hypotenuse(let it will be "n" of smaller triangle

Let use Pythagorean theorem

`a^(2) + {b}^(2) = {n}^(2) \\ {20}^(2) + {10}^(2) = {n}^(2) \\ n = √(500)`

Now we need to find hypotenuse(x) of bigger triangle

`{c}^(2) + {n}^(2) = {x}^(2) \\ {9}^(2) + { √(500) }^(2) = {x}^(2) \\ x = √(581)`

The value of x must be rounded to 1 DP, so

`√(581) = 24.1039... \\ √(581) \simeq \: 24.1`

Answer: x=24.1