Question

Harry is trying to solve the equation y = 2x2 − x − 6 using the quadratic formula. He has made an error in one of the steps below. Find the step where Harry went wrong. (1 point)

Step 1: x equals the negative of negative 1 plus or minus the square root of the quantity negative one squared minus 4 times 2 times negative six, end quantity, all over 2 times 2.

Step 2: x equals the negative of negative 1 plus or minus the square root of negative one plus forty-eight all over two times 2.

Step 3: x equals the negative of negative 1 plus or minus the square root of forty-seven all over two times 2.

Step 4: x equals 1 plus or minus the square root of forty-seven all over 4.

Answer 1

The above answer is correct.

Explanation:

I got it right on the test

Answer 2

Step 2

Explanation:

The quadratic formula is given by
`x=-b+-\frac{\sqrt{b^(2)-4ac } }{2a}`

Our equation is y = 2x²-x-6

So here our a = 2, b = -1, and c = -6

We can now plug these numbers into our formula

`x= -(-1) +-\frac{\sqrt{(-1)^(2)-4(2)(-6) } }{2(2)} = 1 +-(√(1+24) )/(4) = 1+-(√(25) )/(4)`

Step 2 is incorrect because it states that "x equals the negative of negative 1 plus or minus the square root of negative one plus forty-eight all over two times 2."

The correct statement would be "x equals the negative of negative 1 plus or minus the square root of positive one plus forty-eight all over two times 2.", because the square of a negative is positive, resulting in a positive one.

Since this step is incorrect, the steps after are also incorrect, but Harry went wrong at Step 2