How many milliliters of 1.50 M magnesium sulfate soulution is required to supply 2.50 mole of this salt?

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Jon Limjap · Answer 1 · 2021-07-02T08:12:45+0000

Answer:

1670 ml

Step-by-step explanation:

molarity x Volume (Liters) = moles => Volume (Liters) = moles/Molarity

Volume needed = 2.50mol/1.50M = 1.67 Liters = 1670 ml.