Final answer:
To find the mass of 4.50 moles of Ba(NO2)2, you calculate its molar mass using atomic masses and multiply by the number of moles. The result is 1176.03 grams for 4.50 moles of Ba(NO2)2.
Step-by-step explanation:
To calculate the mass of 4.50 moles of Ba(NO2)2, you first need to find its molar mass by adding the atomic masses of barium (Ba), nitrogen (N), and oxygen (O) from the periodic table. The molar mass of Ba(NO2)2 is calculated as follows:
(1 mol Ba)(137.33 g/mol) + (2 mol N)(14.01 g/mol) + (4 mol O)(16.00 g/mol) = 261.34 g/mol
Then, you multiply the molar mass by the number of moles:
(4.50 moles) × (261.34 g/mol) = 1176.03 grams
Therefore, there are 1176.03 grams in 4.50 moles of Ba(NO2)2.