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The drama club is selling short-sleeved shirts for $5 each, and long-sleeved shirts for $10 each. They hope to sell all of the shirts they ordered, to earn a total of $1,750. After the first week of the fundraiser, they sold StartFraction one-third EndFraction of the short-sleeved shirts and StartFraction one-half EndFraction of the long-sleeved shirts, for a total of 100 shirts. How many short-sleeved shirts were ordered?

How many long-sleeved shirts were ordered?

User Roldan
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8.1k points

2 Answers

6 votes

Answer:

b

Explanation:

i did it on edge

User Ganesh Kathiresan
by
7.4k points
7 votes

Answer:

  • 150 short-sleeved shirts
  • 100 long-sleeved shirts

Explanation:

Let S and L represent the numbers of short- and long-sleeved shirts ordered.

The expected earnings were ...

5S +10L = 1750

The number sold was ...

(1/3)S + (1/2)L = 100

We can multiply the first equation by 1/5 and the second equation by 6 to put the equations into standard form:

  • S +2L = 350
  • 2S +3L = 600

Subtracting the second equation from twice the first gives ...

2(S +2L) -(2S +3L) = 2(350) -(600)

L = 100 . . . . . . simplify

2S +3(100) = 600

S = 150

150 short-sleeved and 100 long-sleeved shirts were ordered.

User Michael Van Gerwen
by
8.5k points
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