Question

A farmer has a large field that is x feet in length. He wants to fence in a rectangular section in the middle of the field, leaving a length of 100 feet of open field beyond each end of the fenced rectangle. He also wants the width of the fenced-in space to be 100 feet less than its length, as shown in the diagram.

Find the equation in standard form for the area of the fenced-in section in terms of the length of the field.
(area = length • width)

Answer 1

y = x2 − 500x + 60,000

Explanation:

The length of the fenced-in section is (x − 200) feet, and the width is (x − 300) feet.

area of the fenced-in section = length • width

y = (x − 200)(x − 300)

= x2 − 300x − 200x + 60,000

= x2 − 500x + 60,000

Answer 2

y= x^2 − 500x + 60,000

Explanation:

Other loser made a mistake

The length of the fenced-in section is (x − 200) feet, and the width is (x − 300) feet.

area of the fenced-in section = length • width

y = (x − 200)(x − 300)

= x^2 − 300x − 200x + 60,000

= x^2 − 500x + 60,000