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A rectangular park is 50 meters wide and 90 meters long. Give the length and width of another rectangular park that has the same perimeter but a smaller area.

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Answer:


l = 100\,m and
w = 40\,m

Explanation:

The formulas for the area and perimeter of a rectangle are, respectively:


A = w\cdot l


p = 2\cdot (w + l)

The perimeter is equal to:


p = 2\cdot (50\,m + 90\,m)


p = 280\,m

Area is likewise equal to:


A = (50\,m)\cdot (90\,m)


A = 4500\,m^(2)

Then, equations are now described:


A = w \cdot l


140\,m = w + l

Likewise, the equation of area is simplified afterwards:


A = (140\,m - l)\cdot l


A = 140\cdot l - l^(2)

The area is reduced inasmuch as length is increased. Let assume that length is 100 meters. The length and width are described herein:


l = 100\,m and
w = 40\,m

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