Question

What are the solutions to 2x^2+7y=4 ? Select all that apply.

1/2
4
-1/2
-4
7
-7

Answer 1

x = -1/2 , 4

Step-by-step explanation:

1) If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.

2x+1=0

x−4=0

2) Set the first factor equal to 0.

2x+1=0

3) Subtract 1 from both sides of the equation.

2x=−1

4) Divide each term by 2 and simplify.

2x/2= −1/2

5) Cancel the common factor of 2.

x= −1/2

6) Move the negative in front of the fraction.

x = −1/2

7) Set the next factor equal to 0 and solve.

x=4

8) The final solution is all the values that make

(2x+1)(x−4) = 0 true.

9) x = −1/2 , 4