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What is the molarity (concentration) of 2.53 L of NaOH which exactly neutralizes 5.0L of 1.25 M HCl?

User Juancn
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1 Answer

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Answer:

The concentration of NaOH is 2.47 M

Step-by-step explanation:

The equation of the reaction is

HCl (aq) + NaOH(aq) ------> NaCl(aq) + H2O(l)

Given;

Concentration of acid CA= 1.25 M

Volume of acid VA= 5.0L

Concentration of base CB= ????

Volume of base VB= 2.53 L

Number of moles of acid NA= 1

Number of moles of base NB= 1

From;

CAVA/CBVB= NA/NB

CAVANB= CBVBNA

CB= CAVANB/VBNA

CB= 1.25 × 5.0 ×1 / 2.53×1

CB= 2.47 M

Therefore the concentration of NaOH is 2.47 M

User Dan Randolph
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