Question

A hydraulic press has a large circular piston of radius 0.8m and circular plunger of radius 0.1m . A force of 200N is exerted by a plunger . Find the force exerted on the piston

Answer 1

`F_(o)=12800 N`

Step-by-step explanation:

Let's use the Pascal principle:

`P_(i)=P_(o)`

`(F_(i))/(A_(i))=(F_(o))/(A_(o))`

Where:

F(i) is the input force, 200 N

F(o) is force exerted on the piston

A(i) is the area of the plunger (A =πr(i)²)

A(o) is the area of the piston (A =πr(o)²)

`F_(o)=(A_(o)F_(i))/(A_(i))`

`F_(o)=(r_(o)^(2)F_(i))/(r_(i)^(2))`

`F_(o)=(0.8^(2)*200)/(0.1^(2))`

`F_(o)=12800 N`

I hope it helps you!