Question

Find a cubic function with the given zeros. Square root of seven., -Square root of seven., -4 f(x) = x3 + 4x2+ 7x - 28 f(x) = x3 + 4x2 - 7x - 28 f(x) = x3 - 4x2 - 7x - 28 f(x) = x3 + 4x2 - 7x + 28

Answer 1

f(x) = x^3 + 4x^2 - 7x - 28

Explanation:

If the roots of this cubic function are Square root of seven, -Square root of seven, -4, then the factors must be (x^2 - 7)(x + 4).

Multiplying this out, we get f(x) = x^3 + 4x^2 - 7x - 28.

Note: Please use " ^ " to indicate exponentiation.