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A uniform rod of length l and mass m rests on supports at its ends. The right support (white triangle) is quickly removed. a) What is the force from the left support immediately thereafter? A uniform rod of length 2r and moment of inertia rests on top of two supports, each of which is a distance d away from the center where is a constant. The right support (white triangle) is quickly removed. b) What is the force from the left support immediately thereafter?

User MFerguson
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Answer:

Step-by-step explanation:

For solving this question we will be using Newton's second law of motion in 2 different formats.

F = ma and
\tau = I\alpha

Here F = net external force applied on the body

m = mass of the body

a = acceleration of the centre of mass of the body


\tau = net external torque on the body

I = moment of inertia of the body about given axis


\alpha = angular acceleration of the body

These are 2 forms of Newton's second law of motion first one is from transnational motion and second for rotational motion.

Kindly check the attached images below to see further step by step explanation to the question above.

A uniform rod of length l and mass m rests on supports at its ends. The right support-example-1
A uniform rod of length l and mass m rests on supports at its ends. The right support-example-2
A uniform rod of length l and mass m rests on supports at its ends. The right support-example-3
User NabilS
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