A spring with a spring constant of 5.25N/m applies a force of 8.50N when it is stretched. How much was the spring compressed?

asked Feb 14, 2023 197k views

6 votes

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2 votes

Answer:

1.62

Step-by-step explanation:

F = kx

8.5 = 5.25 * x

8.5/5.25 = 1.62

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