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A spring with a spring constant of 5.25N/m applies a force of 8.50N when it is stretched. How much was the spring compressed?

A spring with a spring constant of 5.25N/m applies a force of 8.50N when it is stretched-example-1

1 Answer

2 votes

Answer:

1.62

Step-by-step explanation:

F = kx

8.5 = 5.25 * x

8.5/5.25 = 1.62

User Victor Chelaru
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