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Select the two values of x that are roots of this equation x2+3x-3=0

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Answer:

x= (-3i-√3)/2

x= (3i+√3)/2

Explanation:

you have to use the quadratic formula which is (-b±√b^2+4ac)/2(a)

a=1

b=3

c= -3

when you plug the numbers into the formula, you get a negative in the square root, so you have to bring out an Imaginary number which is i and connect it with your -b value.

in this case, you only have to switch out the plus and the minus strictly because of the imaginary number

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