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The specific heat of silver is 0.24 J/g°C. If 15.4 g of silver absorb 332 J heat, how much will the temperature of the silver increase?

User Amaranth
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1 Answer

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Final answer:

To calculate the temperature increase, use the heat equation q = m × c × ΔT. Given that 15.4 g of silver absorb 332 J and the specific heat is 0.24 J/g°C, solving for ΔT yields a temperature increase of approximately 89.8°C.

Step-by-step explanation:

To calculate how much the temperature of the silver will increase when it absorbs heat, you can use the formula:

q = m × c × ΔT

where

  • q is the heat absorbed in joules (J)
  • m is the mass in grams (g)
  • c is the specific heat in joules per gram per degree Celsius (J/g°C), and
  • ΔT is the change in temperature in degrees Celsius (°C).

We can rearrange the formula to solve for ΔT (change in temperature):

ΔT = q / (m × c)

In this case

  • q = 332 J
  • m = 15.4 g
  • c = 0.24 J/g°C

Therefore, the change in temperature is:

ΔT = 332 J / (15.4 g × 0.24 J/g°C) = 332 J / (3.696 J/°C) ≈ 89.8°C

The temperature of the silver will increase by approximately 89.8°C.

User Brandrew
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