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If 135.7 J of heat are added to 54.0 g of water initially at 25.0 °C . What is the final temperature of the water?

User Rmalouf
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1 Answer

4 votes

Answer:

The final temperature of the water is 25.6 °C.

Step-by-step explanation:

We have,

Heat added to water is 135.7 J

Mass, m = 54 g

Initial temperature was 25 °C

It is required to find the final temperature of the water. The heat added when temperature is increased is given in terms of specific heat capacity as :


Q=mc(T_f-T_i)


T_f is final temperature

c is specific heat capacity, for water,
c=4.184\ J/g^(\circ) C

So,


T_f=(Q)/(mc)+T_i\\\\T_f=(135.7)/(54* 4.184)+25\\\\T_f=25.6^(\circ) C

So, the final temperature of the water is 25.6 °C.

User Ellee
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