Question

A bag contains 2 red marbles, 3green marbles, and 4 blue marbles. If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble will be green and the second will be red?

Answer 1

6/81

there are 9 marbles and 3 are green so 3/9 and 2 are red so2/9 then times to get 6/81