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The cup was filled at a constant rate. It started empty. After 2 seconds, it held 70 cm^3 of water.

Find the percent of the cup that is filled with water after 3 seconds.

The cup was filled at a constant rate. It started empty. After 2 seconds, it held-example-1
User Smart
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Answer:

About 90%

Explanation:

If the cup was filled at a constant rate, then the cup fills at 70/2=35 cubic centimeters per second. The formula for the volume of a cone is
(1)/(3) \pi r^2 h, or in this case
(112)/(3)\pi cubic centimeters. After 3 seconds, the cup would have 35*3=105 cubic centimeters of water inside of it, or about 89.52% which rounds to 90%. Hope this helps!

User Thomasb
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