Answer:
![68\%](https://img.qammunity.org/2021/formulas/mathematics/college/rgtdllm0s87y0y69r6gzcqtyfrhl2uzlle.png)
Explanation:
Let A be the event that Daniel receives call from SeaWorld.
Probability of event A, P(A) =
Let B be the event that Daniel receives call from Central Park Zoo.
Probability of event B, P(B) =
![48\%](https://img.qammunity.org/2021/formulas/mathematics/college/j5sf825j7feuitoitizup9x10a30rzf5ux.png)
Probability that Daniel receives calls from both SeaWorld and Central Park Zoo:
![P(A \cap B) = 15\%](https://img.qammunity.org/2021/formulas/mathematics/college/9h760jxbz3nkppsqfxbno1jcw3bx16nanx.png)
We know that formula:
Probability that Daniel receives call from either SeaWorld or Central Park Zoo but not both:
![P(A \cup B) = P(A) + P(B) - P(A \cap B)\\\Rightarrow P(A \cup B) = 35\% + 48\% - 15\%\\\Rightarrow P(A \cup B) = 68\%](https://img.qammunity.org/2021/formulas/mathematics/college/kwfcl2m8svkuxmvc1ujej95hcbioclq4yl.png)
Hence, required probability is
.