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Exponential form of log_7(7)=2x + 2

1 Answer

5 votes

Answer:

The value of x is -1/2 .

Explanation:

You have to use Logarithm Law,


{a}^(x) = y => log_(a)(y) = x

So for this question :


log_(7)(7) = 2x + 2


1 = 2x + 2


2x = - 1


x = - (1)/(2)

User DavidJCobb
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