Answer:
7ax2+14ax−x2−35a−2x+5
Explanation:
(7a+−1)(x2+2x+−5)
=(7a)(x2)+(7a)(2x)+(7a)(−5)+(−1)(x2)+(−1)(2x)+(−1)(−5)
=7ax2+14ax−35a−x2−2x+5
=7ax2+14ax−x2−35a−2x+5
(7a - 1) (x² +2x -5) =7a*((x² +2x -5) + (-1)*(x² +2x -5)
= 7a*x² + 7a*2x + 7*(-5) +(-1)*x² +(-1)*2x + -5*-1
= 7ax² + 14ax - 35 - x² -2x + 5
= 7ax² - x² + 14ax - 2x -30
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