Answer:
HH x HH, HH x Hh, HH x hh, Hh x Hh, Hh x hh, hh x hh.
Step-by-step explanation:
In a community in Venezuela, an allele for Huntington’s disease (represented by the letter H) is completely dominant to the allele for no Huntington’s disease (represented by a lowercase h).
The three possible parental genotypes are HH, Hh, and hh.
There are six possible crossings that can be made between these genotypes. These are HH x HH, HH x Hh, HH x hh, Hh x Hh, Hh x hh, hh x hh.
HH x HH
Genotype: All HH
Phenotype: all express the huntington's disease (prob: 1)
HH x Hh
Genotype: 1/2HH 1/2Hh
Phenotype: all express the huntington's disease (prob: 1)
HH x hh
Genotype: All Hh
Phenotype: all express the huntington's disease (prob: 1)
Hh x Hh
Genotype: 1/4HH, 1/2Hh, 1/4hh
Phenotype: 3/4 express the disease, and 1/4 do not express the disease
Hh x hh
Genotype: 1/2Hh 1/2hh
Phenotype: 1/2 express the disease, and 1/2 do not express the disease.
hh x hh.
Genotype: All hh
Phenotype: All do not express the huntington's disease (prob: 1)