Question

1. what are "odds for" stopping on a 2, 3, 7, 10?

2. What are the "odds against" stopping on a number less than 5.

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Answer 1

Question 1

"Odds for" - Number of successes : Number of failures

Number of success = 2, 3, 7 or 10

Number of failures = 1, 4, 5, 6, 8, 9, 11, 12

⇒ odds for stopping on 2, 3, 7 or 10 = 4/8 = 1/2

Question 2

"Odds against" - Number of failures : Number of successes

Number of success = 1, 2, 3, 4

Number of failures = 5, 6, 7, 8, 9, 10, 11, 12

⇒ odds against stopping on 1, 2, 3 or 4 = 8/4 = 2

Answer 2

• 1) 1/2, 2) 2

Explanation:

#1

• Number of total outcomes is 12 (numbers 1 through 12)
• Favorable outcomes are 2, 3, 7, 10, total number is 4
• Unfavorable outcomes are the rest of numbers, total number is 8

The 'odds' is

• Odds for (2, 3, 7, 10) = 4/8 = 1/2

#2

• Number of total outcomes is 12
• Number of favorable outcomes is 4 (numbers less than 5)
• Number of unfovorable outcomes is 8 (the rest of numbers)

The 'odds against' is

• Odds against (< 5) = 8/4 = 2/1 or 2