Question

PLEASE HELP ASAP!

Hydrogen reacts with nitrogen to form ammonia according to equation 3 H2(g) + N2(g) → 2 NH3(g)

A. How many grams of NH3 can be produced from 4.27 mol of N2 and excess H2?

B. How many grams of H2 are needed to produce 13.01g of NH3?

C. How many molecules (not moles) of NH3 are produced from 0.0235 g of H2?

Answer 1

A. 145.2 g NH3

B. 0.76 g H2

C. 1.41 x 10^22 molecules NH3

Step-by-step explanation:

A. 1 mol N2 -> 2 mol NH3

4.27 mol N2 -> x

x= (4.27 mol N2 * 2 mol NH3)/1 mol N2 x= 8.54 mol NH3

1 mol N2 -> 17 g

8.54 mol N2 -> x x= 145.2 g NH3

B.

2 g H2 -> 34 g NH3

x -> 13.01 g NH3

x= 0.76 g H2

C.

2 g H2 -> 34 g NH3

0.0235 g H2 -> x

x= 0.39 g NH3

0.39 g NH3 (1 mol NH3/17 g NH3)(6.023 x 10^23 molecules/1 mol NH3) =

1.41 x 10^22 molecules NH3