Question

Compute the value of the discriminant and give the number of real solutions of the quadratic equation. -9x to the second power-6x-1=0

Answer 1

Answer:
discriminant=0
Number of real solutions=1


Explanation:

Given the equation:
-9x^2-6x-1=0
Let a: coefficient of x^2
Let b: coefficient of x
Let c: constant
a=-9
b=-6
c=-1
The formula of the discriminant is given by:
discriminant= b^2 - 4ac
discriminant= (-6)^2 - 4(-9)(-1)
= 36 - 36 = 0
We know that:
If discriminant<0 then the equation has no real root
If discriminant=0 the equation has one real root
If discriminant>0 the equation has 2 real roots

Here we got discriminant=0 so the quadratic equation has 1 real root.