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Sin²a+sin²a.tan²a=tan²a​

Sin²a+sin²a.tan²a=tan²a​
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Sin²a+sin²a.tan²a=tan²a​

User PalFS
by
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1 Answer

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Answer:

# sin²A (1+tan²A)

# sin²A(sec²A)

# sin²A(1/cos²A)

# sin²A/cos²A=tan²A

User David Wengier
by
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