47.0k views
0 votes
Select the graph that represent the equation (x-6)^2+(y+7)^2=16

User Cardoso
by
7.8k points

2 Answers

5 votes

Answer:

Given equation

(x-6)^2+(y+7)^2=16

centre (6,-7) and radius 4.

Explanation:

The equation of a circle is (x - a)² + (y - b)² = r²

the radius is r

the centre is (a, b)

Given equation

(x-6)^2+(y+7)^2=16

so ,

a = 6

b = - 7

r² = 16


r = \pm √(16)

r = 4

Therefore, the circle with centre (6,-7) and radius 4.

User Kia Raad
by
8.2k points
5 votes

Answer:

This is a circle with centre (6,-7) and radius 4.

Explanation:

The equation of a circle has the following format:


(x - x_(0))^(2) + (y - y_(0))^(2) = r^(2)

In which r is the radius(half the diameter) and the centre is the point
(x_(0), y_(0))

In this question:


(x-6)^(2) + (y+7)^(2) = 16

So


x_(0) = 6, y_(0) = -7


r^(2) = 16


r = \pm √(16)

The radius is the positive value.


r = 4

So this is a circle with centre (6,-7) and radius 4.

User Kshama
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories