Question

What is the radius of a circle with a center at (3,2) and a point on the circle at (9,2)

Answer 1

-The result for the radius:

`6 = r`

-The result for the equation of a circle:

`(x-3)^2+(y-2)^2=36`

Explanation:

The equation of a circle is:

`(x-h)^2+(y-k)^2=r^2` where the center is represented as
`(h,k)`, the point is known as
`(x,y)`, and the radius is represented as
`r` .

-Use the center (3,2) and the point (9,2) for the equation:

`(9-3)^2+(2-2)^2=r^2`

-Then, solve the equation to find the radius:

`(9-3)^2+(2-2)^2=r^2`

`(6)^2+0=r^2`

`36 =r^2`

`√(36) = √(r^2)`

`6 =r`

So, the radius is 6.