From the inscription in the circle and the variables provided, we can conclude that the radius of the circle would be 5 units.
What is the radius of the circle?
It is a rule that the angle in a semicircle is equal to 90°. This means that the angle ACB is equal to 90°. Angle ACB is also a right-angle triangle.
So,
AB² = AC² + BC² (According to the Pythagoras theorem)
AB² = 6² + 8²
AB² = 100
AB =√100
AB = 10
AB = the diameter and radius = diameter/2
So, the radius = 10/2
= 5 units.
Complete Question:
Angle C is inscribed in circle O. Overline AB is a diameter of circle 0. What is the radius of circle O? [blank] units