Question

400.0 ml of a gas are under pressure of 80.0 kpa what would the volume of the gas be at a pressure of 100.0 kpa

Answer 1

The final volume is 320 mL at pressure of 100 kPa.

Explanation:

Boyle's law gives the relation between volume and pressure of a gas. It states that at constant temperature, volume is inversely proportional to its pressure such that,

`V\propto (1)/(P)\\\\P_1V_1=P_2V_2`

Let

`V_1=40\ mL\\\\P_1=80\ kPa\\\\P_2=100\ kPa`

We need to find
`V_2`. Using above equation, we get :

`V_2=(P_1V_1)/(P_2)\\\\V_2=(400* 80* 10^3)/(100* 10^3)\\\\V_2=320\ mL`

So, the final volume is 320 mL at pressure of 100 kPa.